Question
Calculate the index of refraction for a medium in which the speed of light is 2.012×108 m/s2.012 \times 10^8 \textrm{ m/s}, and identify the most likely substance based on Table 25.1.
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Final Answer

n=1.490n = 1.490
This is polystyrene.

Solution video

OpenStax College Physics, Chapter 25, Problem 7 (Problems & Exercises)

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Video Transcript
This is College Physics Answers with Shaun Dychko. The index of refraction equals the speed of light in a vacuum divided by the speed of light in the material. So, that's 2.997 times ten to the eight meters per second divided by 2.012 times ten to the eight meters per second, giving an index of refraction of 1.490. I'm looking at the table 12.1 giving us index refractions of different materials. This is polystyrene.