Question
What current flows through the bulb of a 3.00-V flashlight when its hot resistance is 3.60 Omega3.60\textrm{ }\textrm{Omega}?
Question by OpenStax is licensed under CC BY 4.0
Final Answer

0.833 A0.833\textrm{ A}

Solution video

OpenStax College Physics for AP® Courses, Chapter 20, Problem 18 (Problems & Exercises)

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Video Transcript
This is College Physics Answers with Shaun Dychko. We want to know what the current is through a 3.60 ohm bulb in a flashlight that operates at 3.00 volts. So the voltage is current multiplied by resistance and so we can solve for the current by dividing both sides by R then we get that I is V over R. So that's 3.00 volts divided by 3.60 ohms, which is 0.833 amps.