Question
What is the potential 0.530×1010 m0.530 \times 10^{-10} \textrm{ m} from a proton (the average distance between the proton and electron in a hydrogen atom)?
Question by OpenStax is licensed under CC BY 4.0
Final Answer

27.1 V27.1 \textrm{ V}

Solution video

OpenStax College Physics for AP® Courses, Chapter 19, Problem 25 (Problems & Exercises)

OpenStax College Physics, Chapter 19, Problem 25 (PE) video thumbnail

In order to watch this solution you need to have a subscription.

Start free trial Log in
vote with a rating of votes with an average rating of .

Calculator Screenshots

  • OpenStax College Physics, Chapter 19, Problem 25 (PE) calculator screenshot 1
Video Transcript
This is College Physics Answers with Shaun Dychko. The potential from a point charge is K Q over R. So, Coulombs constant times the charge divided by the distance from the charge. And, this is the potential difference between the distance R from the charge and a potential of zero at infinity. And, this is going to be 8.99 times ten to the nine Newton meters squared per Coulombs squared times 1.60 times ten to the minus 19 Coulombs, because that's the charge of the proton. And, divide by 0.530 times ten to the minus ten meters, giving us a potential of 27.1 volts.